Samsung UE46ES6100 Damaged Backlight: Picture Dims, BN44-00518B Power Supply, SLC5012M Driver

On TV, the image dims from halfway down. I am looking for a power supply diagram or practical knowledge whether to focus on controlling the backlight or LEDs. BN44-00518B power supply with SLC5012M controller. I didn't find the power supply diagram, even the PDF SLC is a problem. I made several LEDs, but with full backlight (then the entire backlight went out as a result of damage to one or more diodes connected in series). Here, the backlight is edge-like and the symptom is different because the backlight is only half functional. Some people will probably be outraged that I'm asking before disassembling the panel, but I admit that when I take out these delicate matrices (especially those above 42"), "sweat runs down my ass".
Please give me suggestions.

Hello.
What is the matrix there? Give the designation.

LTJ460HW05-V matrix.

You need to make precise measurements of the voltage on the backlight plug.
Some backlight branch is not working for you. You need to locate which is not working. You can compare the voltages (working branches with bends had similar voltages). The most important thing to locate it, depending on the system solution, one or more branches may not work. Individual branches should be terminated with power-to-ground transistors.

Hello.
I do not know the systemic solution that exists there.
But it may also be that there are only two backlight branches, one from the bottom of the screen. and the other from the top of the screen. Then you check them separately by applying voltage to them. Backlight plug then disconnected from the board. Approximate value of nap. needed to check, you will then have on the good working one
branch. Then you will find out if the backlight in the matrix is damaged, part of it
damaged inverter. When checking the backlight from a separate power supply, first connect a slightly lower voltage, and necessarily through a resistor in series (for safety).
Greetings.

Well, look at the SM from BN44-00517?, the schematic base of this forum or Link_ ??????? ????? BN44-00517A

The wanted 20-pin "s chip is there
SSC2S110
SLC5012M

Apparently the equivalent of the LX1692A Link_zza behind the Chinese wall

!! I wrote on this forum this year Link
__________________________

BN44-00518B for Samsung UE40ES6307U / UE46ES6100

- field MDS1653, LM358F, systems: SPC7011F, SLC5012M, FA5760

Pod wskazanym przez Liska linku jest sm do BN44_00197A. Układ LX1692A nie jest odpowiednikiem SLC5012M .

Microsemi’s LX1692A is a cost
reduced, third generation Direct Drive
CCFL (Cold Cathode Fluorescent
Lamp) controller. The integrated
controller is optimized to drive
CCFL’s using resonant full bridge

Col. looking "at quickly" at the picture from behind the "Chinese wall" and at this part of the diagram BN44-00197A (allegedly BN44-00517A)
this the pins from LX1692A correspond to the pins of this SLC5012M from the "Chinese picture"
SLC5012M (Magnachip Link ) there is no datasheet! / there is only price 2-4. $ / pc.

so what's the problem?
* mistake in the description of the dog

LE40A676A1M was from dog BN44-00197A, and
(BN44-00199A, which can replace a 197A). Link_ bn44-00199a

Contents Link_ bn44-00518b
BN44-00518B in Samsung UE46ES61000W / UE40ES6307
BN44-00616A also has SLC5012M + weird Link_ scalak SPS1013P_SMS1013_SSOP-14 in Samsung UE46F6200ak

Look at bn44-00199A on LX1692 .. and then with pin. SCL5012M from "Chinese"

I still argue that the LX1692A chip is not the SLC5012M equivalent. The number of legs is just right, the rest are wrong. Besides, as I wrote before: Microsemi's LX1692A is a
Direct Drive CCFL and here we have led.

I wrote about the LX1692 "supposedly", except for il. pin. their description_ nomenclature is correct.
As for the value of RC elements, I did not look at it anymore.

The LX1692 family is described in Link or Link

_________________________________

I looked in the data and
SLC5012M (MAP3312B)

* from Power Supply LED DRIVER BN44-00522B

Quote:

ICP801 SPC7011F
ICS801S STR2A153D
ICM801 UCC25600
IC9800 AS358MTR-G1
IC9804 SLC9012M (MAP9101)
IC9805 SLC9012M (MAP9101)
IC9806 SLC9012M (MAP9101)
IC9807 SLC9012M (MAP9101)
IC9808 SLC9012M (MAP9101)
IC9809 SLC9012M (MAP9101)
IC9810 SLC9012M (MAP9101)
IC9811 SLC9012M (MAP9101)
IC9801 SLC5012M (MAP3312B)
IC9802 SLC5012M (MAP3312B)

And what are you stupidly explaining to the fox? And are you getting into any more CCFL crap?
Your friend showed you idiocy, and you still go into denial and propagate the nonsense that you once wrote.

When you stop writing OFF-TOPIC? Is there no point in the regulations for that, gentlemen moderators?

Nothing can be explained, since there is no datasheet on the SLC5012M, everything "can be pulled up" under the LX ....
as one theorist used to say, "Soviet science knows no such cases">
* today it has to be translated into China.

Especially when you read this "US patent".

____________________
Besides, col. Read first what I wrote and photo. above your post.
SLC5012M (MAP3312B)

Then use col. And you'll be fine.

mery5 on leg 9 and 11 SLC5012M is to be a control signal in both channels and you probably only have one in one.

Skoro "kamyk ruszył lawinę" o tym układzie SLC5012M(MAP3312B) /* SLC4011M napisano w pewnym miesięczniku

** zasada działania

Quote:

Consider the circuit in example channel 1 (CH1), since all channels are implemented on an identical scheme.
Work step-up Converter takes place in two stages.
At the first stage the key on N-MOSFET transistors Q9151, Q9152 open, and current from a voltage source Vdrv flows through the inductor L9151, the core in which energy is stored in the form of a magnetic field. In the second stage, when the key Q9151 Q9152 is closed, the magnetic field energy core of the inductor L decreases, and the throttle occurs EMF the self-inductance, which is formed with the voltage Vdrv and is transmitted through the diode to the capacitor D9151 С9151 and load — LED-line.
With R9153 current sensor that is installed in the circuit and the origins Q9151 Q9152, relieves tension and is fed to the feedback input CS1 (pin. 8) to stabilize the output voltage of the Converter.
In the circuit of the LED line included MOSFET Q9153, which is driven by a PWM signal from the output PWMO1 (pin.2) for control voltage (control brightness) through the LED range. The control signal generated by the microcontroller PWM_DIM1 TV, with the pin.8 of the connector CNM801 via the buffer Q9411 Q9412 is input to PWMI1 (pin.7).
With help of node elements IC9053, IC9051, VR9051 you can set the maximum (threshold) level of the current in the LED strips. A voltage proportional to this level from the output of the repeater on IC9051 is input ILED1 IC9151S (pin4).

___________________

Power Supply LED DRIVER BN44-00523B

Quote:

ICP801 SPC7011F (FA5695N)
ICS801S STR2A153D
ICM801 UCC25600
IC9800 AS358MTR-G1
IC9808 SLC9012M
IC9809 SLC9012M
IC9810 SLC9012M
IC9811 SLC9012M
IC9802 SLC5012M(MAP3312B)
IC9801 SLC5012M(MAP3312B)

Power Supply Inverter BN44-00428B / * PD55B2_BHS

Quote:

ICP801S FA5591N
ICS801S SQD3011K
ICM801S FSFR1800XSL
IC9151S SLC4011M
IC9251S SLC4011M
IC9051 LM358F

To tyle na razie w temacie.

Thank you Lisek for the documentation, she helped me a lot, and I couldn't find it myself. mery5 you will probably have damaged LEDs in your backlight. In my case, two are damaged. Interestingly, one has a break, the other has a short circuit. In order to "cheat the current control system, I would like to install diodes, for example 1n4148, due to the lack of originals. Do you have any experience in this topic?

Read the column on the forum And more
- like a fall. the voltage Uf is on the led in the string
- what is on 1n41448
- what current, how much. mA flows in the led string

I asked about the practical side, because theoretically three 1N4148 for one led should be enough. I don't know what will happen with the brightness adjustment. I meant practice.

Hello.
This is how it comes out if it is not done exactly in sequence.
I wrote earlier that you need to gradually narrow the field where the damage will be.
5 days of time lost, and you still have to start all over again.
If you think a little, measure it, even if you do it carefully, you can check the backlight in the matrix within a few hours.
My friend "Adewag", a power led, and a low-power pulse diode, is similar to "winter shoes for summer flip-flops". These are shoes and these are shoes.
Greetings.

Kol Andrzej4567, thank you for the information, I was 100% sure that the 1N4148 diode is a replacement for the S2LVDIBIBL3BB diode. The only difference I could find was:
1N41 LED lights up pink.
I have a question for Andrzej4567. Why the conclusion that the author of the topic lost 5 days and has to start all over again, since he was active on the forum only on March 13?

PS
March 18 - European Day of the Brain I am asking the moderators for understanding.

Adewag wrote:

I was 100% sure that the 1N4148 diode is a replacement for the S2LVDIBIBL3BB diode. The only difference I could find was:
1N41 LED lights up pink

Good.
By the way, what did you find about the other one? Can you attach any particulars here in the form of files, links?

At the beginning. a little bit here Link
E.g. from China 50pcs (lot) Led series TS731A, 7032 SPBWH1732S1B is around $ 8.99

The rest, e.g. in app.

Hello.
Buddy "mery 5", from the photos available on the internet you can see that you have a matrix that you have
2 illumination cable bundles led outside. There are also 2 backlight connectors, one from the top of the screen and one from the bottom. One beam from the top of the screen and the other beam from the bottom of the screen. There are more cables in the bundle, because these are outputs from individual parts, from one strip.
The led inverter consists of two sub-inverters. One again from the top of the screen and the other from the bottom of the screen. From the photos you can see that each subinverter has only one power transistor in the backlight to ground branch. From this it is clear that these individual parts from the entire one led strip (e.g. only the top of the screen) are connected in series to the outside in the backlight (power supply) socket. So the general illumination scheme is as follows: one branch from the bottom of the screen, and the other branch from the top of the screen. As the wires leading out of the matrix, as well as the connection system in the backlight socket, are practically identical, it is possible to figure out a lot from the measurements which backlight socket is "out of order".
You can also disconnect this serial connection in a suspicious socket and connect a milliammeter to the series. You can do the same with the backlight working
in order to get an idea of the amount of the backlight current. You can also remove the backlight plugs, one time, the other, with the receiver turned off and the receiver turned on, we see which socket (plug) is "out of order". Connect the drive from a separate power supply to the "inactive" plug and then check the lower backlight in the matrix. To sum up, at the beginning, we check the voltage on the backlight electrolytes (each subinverter has its own electrolyte), both should be the same voltage, and the voltage on the twin
the backlight plugs, or the backlight current both at the top of the screen and at the bottom. Finally, when it turns out that one of these two subinverters is not working, taking advantage of the fact that there are also twin solutions and their construction, we make measurements (whether, for example, a keying transistor is working), with the possible replacement of the above-mentioned chip.

Repair of the so-called "non-technological" is possible. Three 1N4148 LEDs for one LED. The difference in the quality of the backlight is imperceptible. Proven, intensively tested for 4 days.
Such shoes :|

PS
Everything we do, we do at our own risk, I do not persuade anyone to use this type of solution. For the safety and correct effect of the repair, use original components.

Okay, but be kind enough to explain just that to me

Adewag wrote:

I was 100% sure that the 1N4148 diode is a replacement for the S2LVDIBIBL3BB diode. The only difference I could find was:
1N41 LED lights up pink

And it would be even better if I could see it. ;)

I will graciously skip the fact that the current around 120mA is not at all nice for a diode made for a nominal current of 200mA. ;)

What do you think? How many LEDs in this backlight could be shorted, and the control would be fine anyway? After all, the current one is. In addition, you can slightly change the parameters of the power supply.
Please do not understand that I recommend jumpers because I do not. ;)

And for the future, try not to hang up with your problems on other users' topics, because it's getting messy.
Although I have reported twice, you will not experience either the topic not divided or even any remarks about non-compliance with the regulations.

Hello. Buddy Adewag, when I offended you so much was "Sorry."
You know very well that 1N4148 is a diode intended mostly for low-power impulse circuits. Known for a long time. After all, it is not any led diode. So that writing that it shines was a big oversight on your part.
Greetings.

Andrzej4567 wrote:

inverter.

Since when does a colleague of the inverter use the LED TV backlight?