How to check with the meter how much the power supply gives Ampere?

Hello
How to check with the meter how much the power supply gives Ampere?
greetings

Hello! The easiest way is to connect the ammeter in series and load the power supply until the voltage drop appears on the power supply, or instead of the ammeter, calculate it using the law of the ohm.
Regards

janek11389 wrote:

Hello! The easiest way is to connect the ammeter in series and load the power supply until the voltage drop appears on the power supply, or instead of the ammeter, calculate it using the law of the ohm.

The method will not work for power supplies without overcurrent protection. The result obtained will be much greater than the real maximum load and will result in the device igniting quickly.

Hello
The power supply will "give" as many amps as it can.
It depends on the load.
If he has security, as much as the security will allow him.
If there are no protections, as much as it can on a short circuit, then it can burn.
Most often I determine the power of the transformer and the strength of the elements used in the construction of the power supply.
Regards.

And it is about measuring, how much can it give the most, or how much does it currently give?

Overall, it would be easy to measure how much current the power supply was giving

Well, because if "how much current it gives" at a given moment - it is an ammeter in series with the power supply.

darkfenriz wrote:

Overall, it would be easy to measure how much current the power supply was giving

I do not know if it is so easy, I once connected an ammeter by mistake
to the battery, I did not have time to read the result, ammeter and battery
it's durable, my fingers were burned, and I had to replace the wires,
because after they lit up (almost like a light bulb) they got quite brittle.

The whole problem with you, I don't think you understand Ohm's Law.
The current flows at a constant voltage that you will connect the load, if the resistance of the load is small, the current is high, if the resistance is high, the current is small. If you make a short circuit, the current will flow limited only by the internal resistance of the power supply or battery.
Usually then everything is destroyed.
So the current depends on the voltage and the load.
I recommend reading a textbook.
Regards

Greetings from physics and logic.
The ammeter measures the current connected in series in the circuit. So you have to put the load-resistor, the bulb in the tested circuit.
If you connected the ammeter to the source in parallel - you just made a short circuit - the ohmmeter has very little resistance (it is practically a voltmeter measuring the voltage drop across a resistor with very low resistance and high load capacity and resistance stability.) If a good battery would be, it should explode.
How to calculate the current of the power supply, take the power consumed from the rating plate, 80% of which (the rest are losses) and use the formula (look for) to calculate the current.
For example 100 VA, i.e. 80VA available. You have 12 V output, i.e. max 6A.
About!!!! Permanently or temporarily ?? Variable voltage power supply - same number

Just to be precise - because as I read your posts - it could be misinterpreted:

Quote:

Well, because if "how much current it gives" at a given moment - it is an ammeter in series with the power supply.

I mean connecting the ammeter in series with the power supply - and connecting the load to the whole (hence it will say "how much current it gives" at a given moment) - as shown in the figure.

Once, I accidentally shorted the battery terminals (fortunately 6V from the flashlight) ... It got hot and bright ... and the battery went away to the other world.

When it turns on, I know - I didn't notice that the meter was set to amps, not volts.

The battery did not explode because the wires had about 0.1 ohms of resistance - it probably flowed from 100A,
batteries, apart from some miniature ones, withstand such currents (as they are only for a short time,
probably a few minutes or a short with a thick bar could destroy it, it will not work with a cable),
I was more worried about the meter - it had a range of only 20A - but it also "survived" and measures correctly.

In my experience: reverse connection of the battery to a simple charger (trafo,
bridge and nothing else) usually burns the bridge or the wires (and sometimes both), the battery rather
it does not matter - the wires themselves, when they are thinner than 10mm2, constitute the fuse.
I do not think I have connected this way, but I have repaired the others a few times.