ESP8266/ESP32: DOUBLE to INT conversion - how to write the first number after the decimal point?

how to solve this problem?

suppose
DOUBLE number = 23.4;

int digit1 = int(t) / 10; // takes the value 2 (it is OK)
int digit2 = int(t) % 10; // assumes value 3 (it is OK)

double temp = int(number) - number; // temp takes the value -0.4 (it is OK)
temp = abs(temp); // temp takes the value 0.4 (it is OK)

int W = temp * 10; // 0.4 * 10

Serial.println(W); is 5 !!! (why is it always 1 more) ????

How to get around this, in total it needs to write the first number after the decimal point to the INT variable. Any other solution ?

What is the result of the following command?
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khoam wrote:

What is the result of the following command?

Code: C / C++

Log in, to see the code

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if temp is 0.4 then the result is 3.0000 at Serial.println(temp * 10, 5)

it still rounds strangely.

even so
double t = 23.4;
double partTotal;

int digit3 = modf(t, & integer part)*10; // result 3 !!! should be 4
int digit1 = int(partCalculus) / 10; // result 2 (OK)
int digit2 = int(integer part) % 10; // result 3 (OK)

---- ROZWIAZANE --------------------------------------------------------------------------------
This is how I finally managed to get the correct value, only that overall the method of
calculations almost the same - it's a conundrum yet....

double t = 23.4;
int digit3 = (t*10); // gets 234
Serial.println(digit3); // gets 4

powerT wrote:

if temp is 0.4 then the result is 3.0000 at Serial.println(temp * 10, 5)

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On my ESP32 it is correct. After running the code:
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I get a result of 4.00000