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LE33CZ Linear Regulator: Minimum Input Voltage and Quiescent Current Consumption

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Best answers

What minimum input voltage does the LE33CZ 3.3V linear regulator need to operate properly, and what is its own current consumption?

The LE33CZ needs its input voltage to be at least the 3.3V output plus its dropout voltage, so you should budget about 3.8V minimum; the dropout is 0.2V typical and 0.5V max [#21666178] Under the datasheet’s typical conditions, 3.7V may work, but that is a borderline case [#21666178] With three 1.2V cells (3.6V nominal), the regulator is right on the edge, and as the cells discharge you can fall below a safe margin [#21666189] The 100mA figure discussed in the thread is the regulator’s maximum load current, not its own internal consumption; actual current depends on the load [#21666190]
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  • #1 21666177
    Simon Mak
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    Steve Lawson
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    Mark Harrington
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  • #12 21666188
    Bob Loy
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    Steve Lawson
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Topic summary

✨ The discussion centers on the LE33CZ linear regulator's minimum input voltage requirements and quiescent current consumption. The dropout voltage is typically 0.2V and can reach a maximum of 0.5V, implying a minimum input voltage of approximately 3.8V to maintain a stable 3.3V output. Using three AAA rechargeable batteries (1.2V each, totaling 3.6V) is borderline but may suffice under typical conditions, considering battery discharge characteristics and environmental factors. The importance of consulting the STMicroelectronics datasheet for detailed specifications and dropout voltage curves is emphasized. For reducing output current from 100mA to 80mA without affecting the 3.3V output, it is clarified that current depends on load resistance (Ohm's law), and a transistor or resistor-based current regulation can be used. A JFET transistor circuit is proposed for current control, but it requires additional voltage for proper operation. Alternative solutions like a Joule Thief circuit for driving LEDs at low voltages are mentioned but discouraged due to battery damage risks. The discussion also highlights the need for balanced battery discharge to avoid cell damage. The LED load with forward voltage around 3.2-3.5V and 20mA current per LED is considered in current regulation strategies. Overall, the conversation stresses the importance of datasheet consultation, understanding dropout voltage, load current relations, and careful battery management in regulator applications.
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FAQ

TL;DR: LE33CZ needs 0.2 V typical, 0.5 V max dropout; “It’s 0.2V typical, 0.5V max.” Design worst‑case Vin ≈ 3.8 V for 3.3 V out. [Elektroda, Steve Lawson, post #21666178]

Why it matters: This FAQ helps beginners pick safe input sources, size loads, and avoid LED and battery pitfalls with the LE33CZ.

Quick Facts

What is the LE33CZ dropout voltage?

Dropout is the extra headroom the regulator needs to keep 3.3 V. For LE33CZ, it’s 0.2 V typical and 0.5 V max. Design to the 0.5 V limit for reliability. “It’s 0.2V typical, 0.5V max.” [Elektroda, Steve Lawson, post #21666178]

What minimum input voltage should I design for with 3.3 V output?

Use Vin(min) ≈ Vout + Vdrop(max). For LE33CZ at 3.3 V, budget 3.3 V + 0.5 V = 3.8 V. This covers temperature and load variation, not just typical lab conditions. [Elektroda, Steve Lawson, post #21666178]

Will three 1.2 V NiMH AAA cells reliably power LE33CZ at 3.3 V?

Three fresh cells are about 3.6 V nominal, which is borderline once any cell sags. NiMH cells are flat over most of discharge, but 1.1 V/cell is a common cutoff. Runtime will end early because headroom vanishes before cutoff. [Elektroda, Steve Lawson, post #21666189]

What happens if one cell discharges faster than the others?

Unbalanced cells can drop too low and risk reverse charge under load. That damages cells and shortens life. Keep cells matched and equally aged, and avoid deep discharge to prevent this failure mode. [Elektroda, Steve Lawson, post #21666199]

How do I reduce current from 100 mA to 80 mA without changing 3.3 V?

The regulator doesn’t set current; the load does. Use Ohm’s law. For 3.3 V: 3.3 V / 0.08 A ≈ 41.25 Ω gives ~80 mA into a resistive load. For 100 mA, 33 Ω. Ensure your load is suitable for resistive control. [Elektroda, Steve Lawson, post #21666190]

What is load regulation on LE33CZ?

Load regulation is how tightly the output stays at 3.3 V as current changes. LE33CZ holds within about 25 mV from 0.5 mA to 100 mA. This keeps logic rails stable under normal load steps. [Elektroda, Steve Lawson, post #21666190]

What if my load tries to draw more than the regulator’s limit?

LE33CZ limits at about 150 mA. Beyond that, it drops output voltage to protect itself. Example: a 10 Ω load forces the regulator to reduce Vout to keep current near the limit. [Elektroda, Steve Lawson, post #21666190]

Can I drive white LEDs from a 3.3 V regulator with almost no headroom?

Caution. LEDs are current‑driven, and their forward voltage varies. With Vf ≈ 3.2–3.5 V, a 3.3 V rail leaves little control headroom. Use a constant‑current driver or ensure adequate voltage for a series resistor. “An LED is a current driven device.” [Elektroda, Steve Lawson, post #21666197]

Is a JFET current limiter a good low‑drop solution here?

A JFET plus resistor forms a simple constant‑current source, but it needs extra voltage to regulate. With only a few hundred millivolts available, keeping 80 mA stable is difficult. Consider more headroom or a dedicated LED driver. [Elektroda, Steve Lawson, post #21666197]

How do I check if my 3‑cell pack maintains 3.3 V regulation?

  1. Compute Vin(min) = 3.3 V + 0.5 V = 3.8 V.
  2. Estimate pack at end‑of‑use ≈ 3 × 1.1 V = 3.3 V.
  3. Since 3.3 V < 3.8 V, the regulator will drop out before cells hit cutoff; plan accordingly. [Elektroda, Steve Lawson, post #21666189]

What’s a Joule Thief, and should I use one instead?

A Joule Thief is a tiny boost oscillator that can light an LED from ~0.5 V, even a single cell. It increases runtime from low voltage but risks over‑discharging cells if unprotected. Use only with appropriate low‑voltage cutoff. [Elektroda, Steve Lawson, post #21666201]

Does LE33CZ suit beginners for small 3.3 V projects?

Yes, with proper headroom and load planning. Use 3–4 alkaline cells, a 5 V USB source, or a higher‑voltage pack to keep ≥0.5 V margin, and verify current stays within 150 mA. “You are learning by doing, and that’s the best way.” [Elektroda, Bob Loy, post #21666188]
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