4-bit Counter Design Using 3 Flip-Flops and Input F: Sequence and Minimization

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#1 21684673 04 Jul 2020 05:36

masoud jahani masoud jahani

Anonymous
Post #1
21684673 04 Jul 2020 05:36

Design a 4-bit counter that will count in the shown sequence based on value of input F. Use only three flip flops. Minimize the combinational parts of the design.

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#2 21684674 06 Jul 2020 20:49

Max Maxfield Max Maxfield

Anonymous

Post #2
21684674 06 Jul 2020 20:49

Oooh -- I LOVE this sort of problem -- but I simply don't have the time -- maybe I can noodle on it while watching TV this evening.
Question: Re your PDF, are you sure input F should feed into the right-hand block of combinatorial logic?
Question: If F changes from 0 to 1 or 1 to 0 in the middle of a sequence, are there any rules as to how we should transition from one sequence to the other?
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#3 21684675 07 Jul 2020 00:11

Elizabeth Simon Elizabeth Simon

Anonymous

Post #3
21684675 07 Jul 2020 00:11

This looks suspiciously like a homework problem...
The key to this is noticing that one bit in each sequence doesn't change.I'd recommend to design a 3-bit counter using the flip-flops then see what you have to do with combinitorial logic to get the desired result for each state of F.
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#4 21684676 07 Jul 2020 03:47

Max Maxfield Max Maxfield

Anonymous

Post #4
21684676 07 Jul 2020 03:47

I agree -- this does look like a homework problem -- at first I was excited because I thought it was going to be tricky, but as you say, it's just a 3-bit binary counter -- the combinatorial logic on the input just does the counter function. The combinatorial logic on the output is just a 2:1 multiplexer.
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#5 21684677 07 Jul 2020 04:20

Jack Grubbs Jack Grubbs

Anonymous

Post #5
21684677 07 Jul 2020 04:20

Output c0 is always equal to F so no logic is need for it.
#6 21684678 09 Jul 2020 13:21

ritesh patil ritesh patil

Anonymous

Post #6
21684678 09 Jul 2020 13:21

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4-bit Counter Design Using 3 Flip-Flops and Input F: Sequence and Minimization

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