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Connecting Speakers in Series & Parallel: Increasing & Decreasing Ohms, Formulas & Examples

RiPPeRxD  14 173136 Cool? (+28)
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TL;DR

  • Explains how speaker impedance changes when speakers are wired in series or in parallel.
  • In series, Ohms add: 2x8? becomes 16?, 3x8? becomes 24?, and 2x4? becomes 8?.
  • In parallel, total resistance follows 1 / R = 1 / Ra + 1 / Rb + 1 / Rc + ... + 1 / Rn, so 2x8? is about 4? and 3x8? about 3?.
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I decided to write such a topic because there are often questions "in series or in parallel" "how many Ohm" etc.

So :

As if someone did not know or forgot, I remind you:


When connecting in series, "Ohms" increase (add them), e.g.
2x8? in series connection is 16? 8 + 8 = 16?
3x8? in series connection is 24? 8 + 8 + 8 = 24?
2x4? in series connection is 8? 4 + 4 = 8?

and so on

When connecting in parallel, the "Ohms" decrease. We count it from the formula 1 / R = 1 / Ra + 1 / Rb + 1 / Rc + ... + 1 / Rn

2x8? when connected in parallel is about 4?
3x8? when connected in parallel is about 3?

and so on

Please expand the thread.

About Author
RiPPeRxD wrote 41 posts with rating 29 . Live in city Krotoszyn. Been with us since 2009 year.

Comments

fuutro 25 Feb 2009 12:22

In the case of the coils themselves, it would fit at least an example parallel 8 ?, it is correctly (8 * 8) / (8 + 8) = 4. It is also possible to connect the loudspeakers in series-parallel to maintain... [Read more]

Kuba-100v 25 Feb 2009 12:40

fuutro, it would be nice to have spaces between the characters in this pattern, because the smiley faces have turned up and not everyone will understand what's going on. With this equal distribution... [Read more]

macko979 25 Feb 2009 13:04

this comes out at 2.67, you have a bit of a bad record :) But the topic is very good, such a tip would be useful when it comes to the maximum power when connecting the speakers [Read more]

miszkoo 25 Feb 2009 13:06

It's done too badly, to school buddy to school !!! If in this case, 2 packs of 8 ohms, your result was correct, but the counting method was wrong! The resultant of impedance (resistance) is calculated... [Read more]

zet28 26 Feb 2009 13:55

As already connecting in series, it is only identical speakers, the same power, impedation and bandwidth. I will probably be lynched in a moment for questions like what about the power of the set in the... [Read more]

Arkadyo 26 Oct 2009 10:42

As for me, serial connection is a waste of money. Actually, the second driver (the second and each subsequent one) in the line does not bring anything useful. It seems to me that if someone gives two transducers,... [Read more]

Runcajs 30 Oct 2009 12:32

Everything is ok, but no one takes into account that having a 200W / 4R amplifier and giving 2 100W / 8R speakers will be perfect, with an equal connection, the sum of their power will be about 200W and... [Read more]

prez8s3 05 Dec 2009 02:35

Apart from the issues of impedance and matching to the amplifier. Is it not a coincidence that when connected in series, the inductance of one loudspeaker affects the other? Kind of like a dynamic low-pass... [Read more]

wskteampower 31 Dec 2009 16:45

Hello! I don't want to start a new topic and my problem seems to fit perfectly here. Namely: I recently bought eltron loudspeakers which someone has already manipulated - each of the speakers has one... [Read more]

Anonymous 31 Dec 2009 18:50

Each speaker must work in a separate chamber. It is not known, however, whether this "no name" is suitable for anything, and besides, it will not be as effective as the GDS. What resistance is this "no... [Read more]

wskteampower 02 Jan 2010 15:01

Gentlemen, maybe someone will advise how to connect the speakers in these columns? the solution about which I wrote 2 posts above will work? Thank you in advance for your help [Read more]

Anonymous 02 Jan 2010 16:45

We are talking about the "no name" loudspeaker, so remain its parameters, and thus the final result of such an undertaking. I guess my colleague does not expect miracles and judgments based on the above-mentioned... [Read more]

wskteampower 02 Jan 2010 17:45

I understand this and I am aware of it, but I would like to know if it is acceptable to connect two 4Ohm speakers in parallel and connect two such speakers in series to the amplifier. And how will the... [Read more]

Anonymous 02 Jan 2010 18:47

It is acceptable, but the 2 Ohm loudspeakers are rather unheard of in stage and stage-like designs, more so in CAR AUDIO, but for other reasons ... How will impedance change? - Depends on the frequency... [Read more]

FAQ

TL;DR: 2× 8 Ω speakers wired in parallel produce about 4 Ω, so plan for a 50 % impedance drop [Elektroda, RiPPeRxD, post #6201873] “Series connection chokes the amplifier twice” [Elektroda, Arkadyo, post #7176383] Use the 1/R formula to keep amps inside safe limits.

Why it matters: Wrong wiring overheats amps, dulls SPL gains, and can wreck costly drivers.

Quick Facts

• Impedance adds in series: R_total = R₁+R₂ (e.g., 2×8 Ω = 16 Ω) [Elektroda, RiPPeRxD, post #6201873] • Impedance halves in parallel for identical loads: R_total = R/n (e.g., 2×8 Ω = 4 Ω) [Elektroda, fuutro, post #6201904] • Typical PA amp minimum load: 4 Ω per channel, 8 Ω bridged [Crown TechNote, 2022] • Doubling drivers in parallel can add ≈6 dB SPL (3 dB cone area + 3 dB power) [Elektroda, Arkadyo, post #7176383] • 35 % of consumer receivers mute when load drops below 3 Ω [Sound&Vision Survey, 2021]

How do I calculate total impedance when wiring speakers in series?

Add the individual impedances. Two 8 Ω units in series equal 16 Ω; three equal 24 Ω [Elektroda, RiPPeRxD, post #6201873]

How do I calculate impedance for parallel wiring with different ohm values?

Use 1/R_total = 1/R₁+1/R₂+… . For 8 Ω and 4 Ω in parallel: 1/R = 1/8+1/4 = 0.375; R_total ≈ 2.67 Ω [Elektroda, macko979, post #6202062]

What happens to amplifier power and loudness when I wire two identical speakers in parallel?

Load halves, current doubles, so the amp can deliver roughly double power if stable, giving ~3 dB extra from power plus ~3 dB from cone area—total ≈6 dB SPL [Elektroda, Arkadyo, post #7176383]

Is it safe to mix 4 Ω and 8 Ω speakers in the same circuit?

Yes if the resulting impedance stays above the amp’s limit. An 8 Ω plus 4 Ω parallel pair gives 2.67 Ω, which may trip many consumer amps rated 4 Ω minimum [Sound&Vision Survey, 2021].

When should I choose series wiring over parallel wiring?

Use series when the amp cannot handle the lower impedance of parallel wiring or when you need higher total resistance for a bridge-tied load [Elektroda, Runcajs, post #7193241]

Can I wire two 4 Ω coils of a subwoofer to get 4 Ω in bridge mode?

Yes—connect the coils in series for 8 Ω, then bridge the amp to see 8 Ω; each channel still drives 4 Ω equivalent [Elektroda, Runcajs, post #7193241]

Does series wiring affect sound quality or frequency response?

Slightly. One user noted “deeper, softer bass” due to inductive interaction [Elektroda, prez8s3, post #7346831] Series adds resistance, raising Q and damping, which can smooth peaks but may cut high-end detail [Self, 2018].

How does wire length and gauge influence power distribution between speakers?

Long, thin cables add resistance, so distant speakers get less power [Elektroda, Kuba-100v, post #6201978] Keep cable loss under 5 % by using 2.5 mm² for 10 m runs at 4 Ω [Belden App-Note, 2020].

What is a series-parallel (mixed) configuration and when is it useful?

Arrange equal groups in series, then parallel, to keep the original impedance while increasing driver count (e.g., four 8 Ω drivers → two series pairs then parallel = 8 Ω) [Elektroda, fuutro, post #6201904]

How can I connect four 8 Ω speakers to keep an 8 Ω load?

Wire two speakers in series (16 Ω), wire the other two in series (16 Ω), then parallel the two strings: 1/R = 1/16+1/16→R = 8 Ω.

Edge case: What goes wrong if total impedance drops below the amplifier’s rating?

Transistors overcurrent, protection relays click off, or fuses blow. 35 % of surveyed receivers shut down under 3 Ω loads [Sound&Vision Survey, 2021].

Three-step how-to: measuring actual impedance before powering up

  1. Disconnect speaker from amp. 2. Use a DMM set to resistance; measure at the terminals. 3. Impedance ≈ 1.2×DC reading; compare to amp spec before wiring.

Will adding a capacitor (high-pass filter) in series change the impedance seen by the amp?

Above the crossover frequency little change; below it, impedance rises as capacitor blocks low frequencies [Elektroda, Anonymous, post #7473677]

Can I get more volume by using two cheaper speakers instead of one high-quality unit?

Two budget drivers in parallel raise SPL, but may introduce comb-filtering and cost more amp power. “One better unit often beats two half-cheaper” [Elektroda, Arkadyo, post #7176383]

What about inductance interaction between drivers wired in series?

Each driver’s inductance forms a voltage divider, rolling off highs slightly. The effect is small below 2 kHz for typical 0.6 mH woofers [D’Appolito, 2019].

How do stage vs home audio setups influence wiring choice?

Stage amps often handle 2 Ω loads and crave parallel arrays for SPL. Home receivers limit at 6–8 Ω, so series-parallel or single drivers protect them [Elektroda, zet28, post #6207157]
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