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  • What happens when AC voltage is applied to the capacitor legs? This element behaves differently than a resistor - the resistor allows direct flow of electrons. The current through the resistor is, according to Ohm's law, proportional to the voltage drop across it. In the case of a capacitor, current is drawn in rhythm as the element charges and discharges to a new voltage level.

    The capacitor charges up to the voltage applied to it. It acts as a kind of electricity store - as long as a direct voltage (DC) is applied to this element, it maintains its internal charge. When the voltage changes, a current will flow that will try to compensate for the change. The value of the current flowing will be directly proportional to the rate of change of the charge on the capacitor plates.

    How capacitors work in AC systems


    In the figure above, we can see a simple circuit - a capacitor connected to an AC voltage source (top left). In such a system, between the current (blue line) and the voltage (red line) flowing through the capacitor, we observe a phase shift of exactly 90 ° (?? - exactly 1/4 of the entire cycle of alternating voltage; top right).

    The AC voltage changes cyclically. The greater the capacity of the connected capacitor, the greater the charge will accumulate between its plates, and thus the greater the current that will flow in the system. It will be similar when we increase the frequency of the alternating voltage - the higher it is, the faster the capacitor must charge, and thus the greater the current flowing in the system. Thus - the current depends on the capacitance of the capacitor and the frequency of the alternating signal.

    Capacitive alternating current systems

    How capacitors work in AC systems


    A fully capacitive AC system is one that consists only of an AC voltage source and a capacitor - as shown in the figure above. In this case, a single capacitor is directly connected to the voltage source. As the voltage changes at the source, the capacitor charges and discharges. Current flows through the system all the time - cyclically back and forth. However, no current actually flows through the capacitor. It is the electrons that concentrate first on one of the covers, and then flow through the system and concentrate on the other cover - at no time do they flow through the dielectric separating them, although this may appear to an inexperienced observer.

    Capacitor reactance

    The flow of electrons through the capacitor is directly proportional to the rate of change of voltage on the plates of this capacitor. Here, the proportionality factor is reactance, just like resistance is the proportionality factor of current and voltage in a system with a resistor.

    The reactance is marked with the letter X to distinguish it from the normal resistance for DC voltage (R). However, like the resistance, its unit is the ohm [?]. The following equation describes the dependence of the reactance on the frequency of the alternating signal f (in Hertz) and the capacitance of the capacitor C (expressed in farads).

    $$X = \frac {1} {2 \pi f C} = \frac {1} {\omega C}$$

    As we can see in the above equation - the higher the frequency or capacity, the smaller the reactance and therefore the greater the current - exactly as described above.

    Source: https://www.eeweb.com/profile/andrew-carter/articles/how-capacitors-behave-in-ac-circuits

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    ghost666
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    ghost666 wrote 11960 posts with rating 10225, helped 157 times. Live in city Warszawa. Been with us since 2003 year.
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  • #2 17350213
    metalMANiu
    Level 21  
    The article should indicate in bold that not all capacitors are suitable for AC voltage.
  • #3 17355005
    jendrula60
    Level 12  
    Brightly . Straight. Affordable. You can ? You can .
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  • #4 17357046
    ^ToM^
    Level 42  
    You have to make up your mind and take one position: ;)

    First you write that electrons do not flow through the dielectric (i.e., de facto through the capacitor):

    "It is the electrons [...] that never pass through the dielectric that separates them."


    Where a moment later you write that they flow through the capacitor:

    "The flow of electrons through the capacitor is directly proportional to the rate of change of voltage across the capacitor plates."

    Through the capacitor, i.e. through the dielectric, as there is nothing else to flow through.

    After all, are they flowing or not?
    I will answer right away. Current flows through the capacitor as long as it is AC (or AC). Writing about electrons thus obscures the picture, because the electrons do not flow, but the current does. The whole radio technology is based on the fact that alternating current flows through the capacitors, where it does not flow through the coils (chokes) (chokes choke the current) - ideally. The choke resists the variation of the current.


    Greetings!
  • #5 17357527
    Anonymous
    Anonymous  
  • #6 17359334
    zico111
    Level 10  
    Someone above wrote the very truth here, namely that the current flows through the capacitor. And the electrons don't flow? and they do not flow, which does not mean that the current does not flow. The current flows due to the presence of an electric field (in this case not via electrons in the conductor). Everything is in Maxwell's laws.
  • #7 17393719
    Szyszkownik Kilkujadek
    Level 37  
    zico111 wrote:
    Everything is in Maxwell's laws.

    You're right. I agree. Only these equations can be solved and interpreted by a small handful of people.
    Gradient, divergence, scalar field, vector field, lapsian ... yuck ;-)
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  • #8 17399982
    pupinizator
    Level 15  
    Fortunately, you don't need to refer to Maxwell's Equations to predict the behavior of a (linear) capacitor. It is enough to take two simple equations:

    $$\left\{\begin{matrix} q=C \cdot u \\i=\frac{dq}{dt} \end{matrix}\right. \quad \Rightarrow i=C\frac{du}{dt} $$ The first equation is a conclusion from (perhaps simple?) Electrostatics (i.e. Coulomb's law), the second equation is the definition of electric current.
  • #9 17401277
    ^ToM^
    Level 42  
    However, not mathematically, it follows directly from the above: the charge exchange on the facings of a capacitor over time is equivalent to the flow of electric current through it. The amount of charge exchange over time is directly proportional to the intensity of the current flowing through it.
    So in any case, despite the dielectric break, current flows through the capacitor and energy is transferred.

    Greetings!
  • #10 17404800
    pupinizator
    Level 15  
    ^ToM^ wrote:
    So in any case, despite the dielectric break, current flows through the capacitor and energy is transferred.
    Even a dielectric is not needed. A vacuum is enough.
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  • #11 17407204
    ^ToM^
    Level 42  
    pupinizator wrote:
    ^ToM^ wrote:
    So in any case, despite the dielectric break, current flows through the capacitor and energy is transferred.
    Even a dielectric is not needed. A vacuum is enough.


    A vacuum is a dielectric. It is commonly used in RF technology and in vacuum capacitors.
  • #12 17408048
    pupinizator
    Level 15  
    ^ToM^ wrote:
    A vacuum is a dielectric.
    Are you sure? Take a look at the definition. A dielectric is a material. A (perfect) vacuum is not a material. Maybe it's a detail, but if we are to be precise, let's be "for the pain".
  • #13 17409123
    Szyszkownik Kilkujadek
    Level 37  
    We are one step away from quantum physics ... ;-)
  • #14 17409142
    ^ToM^
    Level 42  
    pupinizator wrote:
    ^ToM^ wrote:
    A vacuum is a dielectric.
    Are you sure? Take a look at the definition. A dielectric is a material. A (perfect) vacuum is not a material. Maybe it's a detail, but if we are to be precise, let's be "for the pain".


    Everything is correct. A vacuum is a dielectric with a constant equal to 1. In the material sense, a vacuum is not a dielectric, as it is the term for the complete absence of matter. In the capacitor between the conductive facings there does not need to be a physical material for it to function, but there has to be a dielectric or no dielectric such as a vacuum. Thus, vacuum, air, and gases fulfilling this function can be said to be a dielectric with a constant equal to 1 or close to one.
    Vacuum capacitors, although they do not have a physical dielectric, have excellent parameters and are commonly used in RF systems. high power. Vacuum capacitors, however, also have disadvantages, above all a small capacity with large dimensions.
    Nevertheless, despite the lack of a physical dielectric, such capacitors work in the same way as all others and conduct alternating current as well as those with a dielectric.
  • #15 20424521
    kstrygner
    Level 1  
    I will write as follows: A capacitor is a specific element. Powered from an "AC" source, it does not itself conduct current through the dielectric, but causes current to flow in the wires connecting it to the power source. One of the participants noticed that it was not a resistor. It is a "storage" of energy on which potential changes are forced in this case by the power source. Hence the flow of current through the wires and powering the generator.
    And the "bidula" capacitor gets hit on its linings with alternating charges, forced to constantly charge and discharge ...

Topic summary

Capacitors behave differently from resistors when AC voltage is applied. While resistors allow direct electron flow proportional to voltage, capacitors store energy and allow current to flow in response to voltage changes. The current through a capacitor is proportional to the rate of change of voltage across its plates. Not all capacitors are suitable for AC applications, and the dielectric material plays a crucial role in their operation. Current flows through the capacitor due to the electric field, even though electrons do not pass through the dielectric. Vacuum capacitors, which lack a physical dielectric, can still function effectively in RF systems. The discussion highlights the importance of understanding the behavior of capacitors in AC circuits, emphasizing their role as energy storage devices that facilitate current flow in connected circuits.
Summary generated by the language model.
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