An alternative to the measure / indicator described above can be the D85-3051AG model. It is bigger (and more expensive), but in my opinion it is more readable. Of course, it also has the ability to calibrate, but "out of the box" it shows what a universal meter, although it is no ;)
The price is about PLN 30 on the Chinese portal. This is how it looks in the pictures:
When this topic has already started again, and there are more and more news on the Chinese market, I would like to ask my dear colleagues what do you think about this gem. https://pl.aliexpress.com/item/4000111098529....scm=1007.13338.192130.0&scm_id=317.133b.1933l =&scm_id=317.133b6.1933l =&scm_id=317.133b.1933l=21 -4a92-b013-47f3fbe4e38d & _t = gps-id: pcDetailBottomMoreOtherSeller, scm-url: 1007.13338.192130.0, pvid: fbca6c31-6583-4a92-b013-47f3fbe4e38d, tpp_buckets% 2361968% 2361933% 2361968% 2361933% 2361968% 2361933% 2361968% 2361933% % 23192 130% 230_3338% 233142% 239 890% 234_668% 232 846% 238 115% 232000_668% 232 717% 237 565% 23773_668% 231000022185% 231000066059% 230_668% 233,422% 2315,392% 23,326
I would be more interested in indicating not the power, but the energy that has been passed through this meter in the time period I am interested in, e.g. how much energy I got from PV panels on a given day, week or month.
Maybe not so much the Chinese forgot, as you forgot to enter the current range. In this case, the shunt will probably not be soldered, but connected with screws. Shunt suitable for the measured current range with a 75mV output (connected to the module).
I will not answer unequivocally, because I do not know what the module you have looks like and whether there is a place for soldering the shunt. I have two types of such modules, both with 10A range. In one there is a piece of wire soldered as a shunt, and in the other one there is no such soldered wire and its role is probably played by the appropriate thickness of the tin on the path. Judging by the shunts for such modules that I saw on the Allegro, for example 50A -75mV, i.e. with a current of 50A, there is a voltage drop of 75mV on it and this voltage drop is measured by the meter and the reader shows it as 50A - I think, because no I played these blocks with electronic meters. So with a 10A shunt, by analogy, the resistance of this shunt should be 0.0075? (7.5 m? so that at a current of 10A there would be a drop of 75mV on it. I admit that I cannot imagine such a precise soldering of such a shunt.